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Instrument 04

Half-life

Order, k and [A]₀ in; the half-life, a countdown of half-lives and [A] at any time out.

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Input

Runs of up to 40 data rows (Bench Pass limit, free during preview).

Result

t½ = 50.0 min

Rate law
rate = k[A]2, k = 0.250 M−1 min−1
[A] at t = 30 min
0.0500 M
Time to [A] = 0.01 M
350 min

Second order: each half-life is twice as long as the one before.

020040060080000.020.040.060.081×2×3×4×t (min)[A] (M)
Decay curve. Dashed lines mark the end of each half-life.

Half-life countdown

Half-lifeLength (min)Ends at (min)[A] then (M)
150.050.00.0400
21001500.0200
32003500.0100
44007505.00 × 10−3
58001,5502.50 × 10−3

The working

Intermediate values are carried to six significant figures; results are rounded to three at the end.

  1. t½ = 1/(k[A]0) = 1 / (0.25 × 0.08) = 50.0 min.
  2. Second order: each half-life starts from half the concentration, so it lasts twice as long as the one before.
  3. [A] at t = 30 min: 1/[A] = 1/[A]0 + kt = 1/0.08 + (0.25 × 30) = 12.5 + 7.5 = 20 M−1, so [A] = 1/20 = 0.0500 M.
  4. Time to [A] = 0.01 M: t = (1/[A] − 1/[A]0) / k = (1/0.01 − 1/0.08) / 0.25 = (100 − 12.5) / 0.25 = 350 min.

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